5/(x^2-7x)=1/(x^2-49)

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Solution for 5/(x^2-7x)=1/(x^2-49) equation:


D( x )

x^2-(7*x) = 0

x^2-49 = 0

x^2-(7*x) = 0

x^2-(7*x) = 0

x^2-7*x = 0

x^2-7*x = 0

DELTA = (-7)^2-(0*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+7)/(1*2) or x = (7-49^(1/2))/(1*2)

x = 7 or x = 0

x^2-49 = 0

x^2-49 = 0

1*x^2 = 49 // : 1

x^2 = 49

x^2 = 49 // ^ 1/2

abs(x) = 7

x = 7 or x = -7

x in (-oo:-7) U (-7:0) U (0:7) U (7:+oo)

5/(x^2-(7*x)) = 1/(x^2-49) // - 1/(x^2-49)

5/(x^2-(7*x))-(1/(x^2-49)) = 0

5/(x^2-7*x)-(x^2-49)^-1 = 0

5/(x^2-7*x)-1/(x^2-49) = 0

x^2-7*x = 0

x^2-7*x = 0

x*(x-7) = 0

x-7 = 0 // + 7

x = 7

x*(x-7) = 0

5/(x*(x-7))-1/(x^2-49) = 0

(5*(x^2-49))/(x*(x-7)*(x^2-49))+(-1*x*(x-7))/(x*(x-7)*(x^2-49)) = 0

5*(x^2-49)-1*x*(x-7) = 0

4*x^2+7*x-245 = 0

4*x^2+7*x-245 = 0

4*x^2+7*x-245 = 0

DELTA = 7^2-(-245*4*4)

DELTA = 3969

DELTA > 0

x = (3969^(1/2)-7)/(2*4) or x = (-3969^(1/2)-7)/(2*4)

x = 7 or x = -35/4

(x+35/4)*(x-7) = 0

((x+35/4)*(x-7))/(x*(x-7)*(x^2-49)) = 0

((x+35/4)*(x-7))/(x*(x-7)*(x^2-49)) = 0 // * x*(x-7)*(x^2-49)

(x+35/4)*(x-7) = 0

( x+35/4 )

x+35/4 = 0 // - 35/4

x = -35/4

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 7}

x = -35/4

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